A lower wattage resistor will heat up too quickly. Also, do not hold the resistor with your bare hand. The current flowing through the resistor will cause the resistor to heat up and you could be burned. A good place to put the resistor is in the main power wire fuse holder the one installed near the battery.

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Simply substitute the resistor for the fuse. A diagram for the capacitor charging setup is shown below. You will need to place a voltmeter across the capacitor to monitor the voltage. Once the voltmeter reads 12 volts or close to it you can remove the voltmeter and replace the resistor with the power fuse.

Alternatively you can measure the voltage across the charging resistor. It should start around 12 volts and slowly work its way down to 0 volts. When the voltage stops changing you have charged the capacitor completely. Another method for charging involves using an old style test light instead of a resistor.

The connection is similar alligator clip on one side, probe on the other but you don't need a voltmeter to monitor voltage. Locate the main power fuse for your audio system. This fuse is installed with your system to prevent damage to the electrical components of your car, but will need to be removed before charging the capacitor. It should be near the battery on the main power line for your audio system.

Remove the main power fuse. This this will provide you a place to install the resistor that will help you charge your capacitor.

This prevents damage to the capacitor and the electrical system. Put the resistor in place of the main power fuse. It is usually recommended to use a resistor that is 1 Watt and , Ohms. A higher impedance Ohm value will charge the capacitor more slowly and prevent damage. Connect the positive terminal of the capacitor to the resistor. Measure the voltage on the capacitor with a voltmeter.

A multi-meter will do the job fine as well. Set it to read DC Volts and put the positive lead of the meter on the positive terminal of the capacitor and the negative lead of the meter to ground. When the meter reads volts, the capacitor is charged. As long as the capacitor is charging, there will be current flowing through the light and the light will shine. Once the capacitor is charged the light will go out because current will no longer be flowing the voltage drop between the power line and the capacitor will be zero.

It is no longer necessary to monitor the status of the capacitor. If you used the light method, you can now remove the test light.

## Capacitors in series (video) | Circuits | Khan Academy

Disconnect the positive terminal of the capacitor from the resistor and disconnect the resistor from the power wire. It is no longer needed, so you can store it away in case you ever need to charge your capacitor again. Replace the main power fuse.

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This will allow your audio system to receive power once again. What do I do if there is no place on a capacitor for a remote wire hookup? Should it come on when the main fuse is put into place, and what would cause the capacitor to power up, but not the amp? Not Helpful 4 Helpful Do I need to use a resistor to charge the capacitor, or can I just use the test light? You can use the test light, but be sure to connect the capacitor in series with the test light. Not Helpful 0 Helpful 2. If both the amp and cap have a remote wire, do I need to split and connect it to both? You will actually just run the remote turn on wire from the amp already hooked up, and then run the turn on to the cap.

Not Helpful 4 Helpful 7.

### Circuits with capacitors

No, it does not matter which one the remote wire goes to first. Not Helpful 1 Helpful 1. I just hooked up a cap in my car and now I'm hearing strange noises coming out my sub-woofer. What could it be? Check the grounds on your cap and amp. Now, let's solve for the amount of charge that this nine farad equivalent capacitor would store when hooked up to the eight volt battery.

## Capacitors in parallel

Using the definition of capacitance, we find that the charge on a nine farad capacitor would be 72 coulombs. And this makes sense, because remember the charge stored on the six farad capacitor was 48 coulombs, and the charge stored on the three farad capacitor was 24 coulombs. So the total charge on the six farad and three farad capacitors is 72 coulombs, which is the same charge that their equivalent capacitor stores. Let's try another problem that's a little more challenging. Say we introduce a 27 farad capacitor into this circuit. When the battery's connected, the capacitors will all store charge and have a certain voltage across them.

So let's try to figure out the charge on and the voltage across all of these capacitors.

Well, to start, we might notice that the three farad and six farad capacitors are still in parallel with each other, which means they have to have the same voltage as each other. But this time, the value of that voltage is not going to be the same as the voltage of the battery. Because even though their negative sides are connected directly to the negative terminal of the battery, their positive sides are not connected directly to the positive terminal of the battery.

## Capacitors in series

This 27 farad capacitor is getting in the way here. Similarly, the voltage across the 27 farad capacitor is also not going to be the same as the voltage of the battery. Because even though it's positive side is connected directly to the positive terminal of the battery, it's negative side is not connected directly to the negative terminal of the battery. So in summary, we don't know the voltage across any of these capacitors. And if we don't know the voltage across any of these individual capacitors, how are we ever going to solve for the charge on these capacitors?

Well, the one thing that we do know is that the voltage across the whole circuit is eight volts. We just don't know the individual voltages across each capacitor. So what we're going to try to do is to replace these individual capacitors with a single equivalent capacitor. To do that, let's start with the six farad and three farad capacitors, because we know those are in parallel. We know they're in parallel because their positive sides are connected directly to each other and their negative sides are connected directly to each other.

Using the rule to combine parallel capacitors, we get that the equivalent capacitance of the three and six farad capacitors is a single nine farad capacitor. So now we have a nine farad capacitor and a 27 farad capacitor. These are connected in series, because they're hooked up one right after the other. Or in other words, the positive side on one capacitor is connected to the negative side on the other capacitor. We can replace these two capacitors with a single equivalent capacitor by using the formula for adding capacitors in series, which is 1 over the equivalent capacitance equals 1 over C1 plus 1 over C2.

So plugging in the values of nine farads and 27 farads, we get that 1 over the equivalent capacitance equals 0. Don't forget to take 1 over this number to get that the equivalent capacitance is 6.

So we can replace the nine farad and 27 farad capacitors with a single 6.